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Using a second variable name resolves the problem. It's weird that you can't do this in bash. But why do I get the same problem with just the line ${input//\n/,} without any assignment?

Suzana
– Suzana

2015-05-27 18:54:46 +00:00
Commented May 27, 2015 at 18:54
2

Because at that point, you're trying to execute the variable's value, not echo it. You have to have an echo command in front of the variable if you're not assigning it (the modified value) to another variable.

John
– John

2015-05-27 18:56:36 +00:00
Commented May 27, 2015 at 18:56

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