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In what shell are piped commands run in parallel? How could that even occur? B has to read A's output (as B's input), which, as far as I'm aware, means A needs to produce an output before B can read it. Additionally, the line that could produce similar behavior using command substitution would be: B $(A), not A $(B), which is the OPs question.

De Novo
– De Novo

2019-01-28 19:24:00 +00:00
Commented Jan 28, 2019 at 19:24
1

@DeNovo : If you have pipe A|B, the usual implementation is to start both processes A and B, and feed the stdout of A to the stdin of B. Without this, a construct such as A|tail -f would not work.

user1934428
– user1934428

2019-01-29 10:09:46 +00:00
Commented Jan 29, 2019 at 10:09

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