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Explore Stack Internal I've written my own Sudo bash function to do that, it works to call functions and aliases :
function Sudo { local firstArg=$1 if [ $(type -t $firstArg) = function ] then shift && $(whichcommand sudo) bash -c "$(declare -f $firstArg);$firstArg $*" elif [ $(type -t $firstArg) = alias ] then alias sudo='\sudo ' eval "sudo $@" else $(whichcommand sudo) "$@" fi } I've written my own Sudo bash function to do that, it works to call functions and aliases :
function Sudo { local firstArg=$1 if [ $(type -t $firstArg) = function ] then shift && $(which sudo) bash -c "$(declare -f $firstArg);$firstArg $*" elif [ $(type -t $firstArg) = alias ] then alias sudo='\sudo ' eval "sudo $@" else $(which sudo) "$@" fi } I've written my own Sudo bash function to do that, it works to call functions and aliases :
function Sudo { local firstArg=$1 if [ $(type -t $firstArg) = function ] then shift && command sudo bash -c "$(declare -f $firstArg);$firstArg $*" elif [ $(type -t $firstArg) = alias ] then alias sudo='\sudo ' eval "sudo $@" else command sudo "$@" fi } I've written my own Sudo bash function to do that, it works to call functions and aliases :
function Sudo { local firstArg=$1 if [ $(type -t $firstArg) = function ] then shift && $(which sudo) bash -c "$(declare -f $firstArg);$firstArg $@"$*" elif [ $(type -t $firstArg) = alias ] then alias sudo='\sudo ' eval "sudo $@" else $(which sudo) "$@" fi } I've written my own Sudo bash function to do that, it works to call functions and aliases :
function Sudo { local firstArg=$1 if [ $(type -t $firstArg) = function ] then shift && $(which sudo) bash -c "$(declare -f $firstArg);$firstArg $@" elif [ $(type -t $firstArg) = alias ] then alias sudo='\sudo ' eval "sudo $@" else $(which sudo) "$@" fi } I've written my own Sudo bash function to do that, it works to call functions and aliases :
function Sudo { local firstArg=$1 if [ $(type -t $firstArg) = function ] then shift && $(which sudo) bash -c "$(declare -f $firstArg);$firstArg $*" elif [ $(type -t $firstArg) = alias ] then alias sudo='\sudo ' eval "sudo $@" else $(which sudo) "$@" fi } I've written my own Sudo bash function to do that, it works to call functions in sudo mode but it does not work withand aliases yet :
function Sudo { local firstArg=$1 if [ $(type -t $firstArg) = function ] then shift && $(which sudo) bash -c "$(declare -f $firstArg);$firstArg $@" elif [ $(type -t $firstArg) = alias ] then alias sudo='\sudo ' shift && sudoeval $firstArg"sudo "$@"$@" else $(which sudo) "$@" fi } If anyone knows why my function does not work with aliases, please feel free to edit my answer.
I've written my own Sudo bash function to do that, it works to call functions in sudo mode but it does not work with aliases yet :
function Sudo { local firstArg=$1 if [ $(type -t $firstArg) = function ] then shift && $(which sudo) bash -c "$(declare -f $firstArg);$firstArg $@" elif [ $(type -t $firstArg) = alias ] then alias sudo='\sudo ' shift && sudo $firstArg "$@" else $(which sudo) "$@" fi } If anyone knows why my function does not work with aliases, please feel free to edit my answer.
I've written my own Sudo bash function to do that, it works to call functions and aliases :
function Sudo { local firstArg=$1 if [ $(type -t $firstArg) = function ] then shift && $(which sudo) bash -c "$(declare -f $firstArg);$firstArg $@" elif [ $(type -t $firstArg) = alias ] then alias sudo='\sudo ' eval "sudo $@" else $(which sudo) "$@" fi }