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lang-bash
execve()finishes, doesexecve()terminate its process, regardless whehterexecve()succeeds or fails? I thought yes, so whenexecve()fails to execute a shell script, it would terminate the subprocess, and the original shell will have to fork a subprocess to execute the script../test.shwith shebang#! /bin/bashis executed via command./test.sh, is it actually executed as/bin/bash ./test.sh? If yes, is it correct to expect bash to runexecve("/bin/bash", ["/bin/bash", "./test.sh"], ...) = 0? But I runstrace -f ./test.sh 2>&1 | less, and only find one call toexecve():execve("./test.sh", ["./test.sh"], [/* 59 vars */]) = 0. Note the difference in the first argument, which is for the executable file.