Revisions to Why does `source foo && true` exit the script in bash?

Typo fix

edited Aug 22, 2018 at 23:11

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source is an alias to the dot . command and the dot command is a so called special command where POSIX describes that these commands exit the whole non-interactive shell in case that an error occurs.

If you call your command via:

bash test.sh

bash does not exit, but when you call:

bash -o posix test.sh

it exits. So either your bash has been compiled to be POSIX compliant by default otor you did call a different shell than bash.

See http://pubs.opengroup.org/onlinepubs/9699919799/utilities/V3_chap02.html#tag_18_14 for the standard.

source is an alias to the dot . command and the dot command is a so called special command where POSIX describes that these commands exit the whole non-interactive shell in case that an error occurs.

If you call your command via:

bash test.sh

bash does not exit, but when you call:

bash -o posix test.sh

it exits. So either your bash has been compiled to be POSIX compliant by default ot you did call a different shell than bash.

See http://pubs.opengroup.org/onlinepubs/9699919799/utilities/V3_chap02.html#tag_18_14 for the standard.

source is an alias to the dot . command and the dot command is a so called special command where POSIX describes that these commands exit the whole non-interactive shell in case that an error occurs.

If you call your command via:

bash test.sh

bash does not exit, but when you call:

bash -o posix test.sh

it exits. So either your bash has been compiled to be POSIX compliant by default or you did call a different shell than bash.

See http://pubs.opengroup.org/onlinepubs/9699919799/utilities/V3_chap02.html#tag_18_14 for the standard.

added 108 characters in body

Source Link

edited Aug 21, 2018 at 11:06

schily

19.8k
5
42
61

source is an alias to the dot . command and the dot command is a so called special command where POSIX describes that these commands exit the whole non-interactive shell in case that an error occurs.

If you call your command via:

bash test.sh

bash does not exit, but when you call:

bash -o posix test.sh

it exits. So either your bash has been compiled to be POSIX compliant by default ot you did call a different shell than bash.

See http://pubs.opengroup.org/onlinepubs/9699919799/utilities/V3_chap02.html#tag_18_14 for the standard.

source is an alias to the dot . command and the dot command is a so called special command where POSIX describes that these commands exit the whole non-interactive shell in case that an error occurs.

If you call your command via:

bash test.sh

bash does not exit, but when you call:

bash -o posix test.sh

it exits. So either your bash has been compiled to be POSIX compliant by default ot you did call a different shell than bash.

source is an alias to the dot . command and the dot command is a so called special command where POSIX describes that these commands exit the whole non-interactive shell in case that an error occurs.

If you call your command via:

bash test.sh

bash does not exit, but when you call:

bash -o posix test.sh

it exits. So either your bash has been compiled to be POSIX compliant by default ot you did call a different shell than bash.

See http://pubs.opengroup.org/onlinepubs/9699919799/utilities/V3_chap02.html#tag_18_14 for the standard.

Source Link

answered Aug 21, 2018 at 8:51

schily

19.8k
5
42
61

source is an alias to the dot . command and the dot command is a so called special command where POSIX describes that these commands exit the whole non-interactive shell in case that an error occurs.

If you call your command via:

bash test.sh

bash does not exit, but when you call:

bash -o posix test.sh

it exits. So either your bash has been compiled to be POSIX compliant by default ot you did call a different shell than bash.

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