Here is a simple script to demonstrates the different between $* and $@:

#!/bin/bash test_param() { echo "Receive $# parameters" echo Using '$*' echo for param in $*; do printf '==>%s<==\n' "$param" done; echo echo Using '"$*"' for param in "$*"; do printf '==>%s<==\n' "$param" done; echo echo Using '$@' for param in $@; do printf '==>%s<==\n' "$param" done; echo echo Using '"$@"'; for param in "$@"; do printf '==>%s<==\n' "$param" done } IFS="^${IFS}" test_param 1 2 3 "a b c" 

Output:

% cuonglm at ~ % bash test.sh Receive 4 parameters Using $* ==>1<== ==>2<== ==>3<== ==>a<== ==>b<== ==>c<== Using "$*" ==>1^2^3^a b c<== Using $@ ==>1<== ==>2<== ==>3<== ==>a<== ==>b<== ==>c<== Using "$@" ==>1<== ==>2<== ==>3<== ==>a b c<== 

In array syntax, the no different when using $* or $@. It only make sense when you use with double quotes "$*" and "$@".

Here is a simple script to demonstrates the difference between $* and $@:

#!/bin/bash test_param() { echo "Receive $# parameters" echo Using '$*' echo for param in $*; do printf '==>%s<==\n' "$param" done; echo echo Using '"$*"' for param in "$*"; do printf '==>%s<==\n' "$param" done; echo echo Using '$@' for param in $@; do printf '==>%s<==\n' "$param" done; echo echo Using '"$@"'; for param in "$@"; do printf '==>%s<==\n' "$param" done } IFS="^${IFS}" test_param 1 2 3 "a b c" 

Output:

% cuonglm at ~ % bash test.sh Receive 4 parameters Using $* ==>1<== ==>2<== ==>3<== ==>a<== ==>b<== ==>c<== Using "$*" ==>1^2^3^a b c<== Using $@ ==>1<== ==>2<== ==>3<== ==>a<== ==>b<== ==>c<== Using "$@" ==>1<== ==>2<== ==>3<== ==>a b c<== 

In array syntax, there is no difference when using $* or $@. It only make sense when you use them with double quotes "$*" and "$@".

Here is a simple script to demonstrates the different between $* and $@:

#!/bin/bash function test_param() {     echo "Receive $# parameters";   echo Using '$*';   echo   for param in $*;  do   echo "==>$param<==";   done;   echo   echo Using '"$*"';   for param in "$*";  do   echo "==>$param<==";   done;   echo   echo Using '$@';   for param in $@;  do   echo "==>$param<==";   done;   echo   echo Using '"$@"';   for param in "$@";  do   echo "==>$param<==";   done } IFS="^${IFS}" test_param 1 2 3 "a b c" 

Output:

% cuonglm at ~ % bash test.sh  Receive 4 parameters Using $*  ==>1<== ==>2<== ==>3<== ==>a<== ==>b<== ==>c<== Using "$*" ==>1^2^3^a b c<== Using $@ ==>1<== ==>2<== ==>3<== ==>a<== ==>b<== ==>c<== Using "$@" ==>1<== ==>2<== ==>3<== ==>a b c<== 

In array syntax, the no different when using $* or $@. It only make sense when you use with double quotes "$*" and "$@".

Here is a simple script to demonstrates the different between $* and $@:

#!/bin/bash test_param() { echo "Receive $# parameters" echo Using '$*' echo for param in $*; do printf '==>%s<==\n' "$param" done; echo echo Using '"$*"' for param in "$*"; do printf '==>%s<==\n' "$param" done; echo echo Using '$@' for param in $@; do printf '==>%s<==\n' "$param" done; echo echo Using '"$@"'; for param in "$@"; do printf '==>%s<==\n' "$param" done } IFS="^${IFS}" test_param 1 2 3 "a b c" 

Output:

% cuonglm at ~ % bash test.sh Receive 4 parameters Using $* ==>1<== ==>2<== ==>3<== ==>a<== ==>b<== ==>c<== Using "$*" ==>1^2^3^a b c<== Using $@ ==>1<== ==>2<== ==>3<== ==>a<== ==>b<== ==>c<== Using "$@" ==>1<== ==>2<== ==>3<== ==>a b c<== 

In array syntax, the no different when using $* or $@. It only make sense when you use with double quotes "$*" and "$@".