How to run a executable file in c++ in Linux?

Question

I am trying to run an executable file within a c++ code. It compiles and run, but it displays a message "permission denied". This same code works on windows, I just use the appropriate file path.

Here is the code I am using

FILE *fp = popen("/home/Int_Outputs/bin/Debug","r"); if (fp == NULL){ std::cout <<"Popen is null" << std::endl; } char buff[50]; fgets(buff,sizeof(buff),fp); std::cout << buff; } return 0; }

but how do I do that, I went to the properties of the executable file of the project and that is the path that shows — TheBBC
– TheBBC, Commented Aug 18, 2015 at 2:02
First of all, open console an type: cd /home/Int_Outputs/bin and then sudo chmod u+r Debug. If that changes nothing, explain what exactly does not work. — Mateusz Grzejek
– Mateusz Grzejek, Commented Aug 18, 2015 at 2:06

Keith Thompson · Accepted Answer · 2015-08-18 02:12:08Z

2

What are the POSIX permissions for that file? To find out, open a terminal shell and do:

$ ls -l /home/Int_Outputs/bin/Debug

You have to make sure that the UID/GID that your application runs as has permission to read the file "/home/Int_Outputs/bin/Debug"

edited Aug 18, 2015 at 2:12

Keith Thompson

266k46 gold badges447 silver badges668 bronze badges

answered Aug 18, 2015 at 2:01

Kal

4214 silver badges7 bronze badges

Sign up to request clarification or add additional context in comments.

3 Comments

TheBBC Over a year ago

well, I am able to run it from the terminal by doing "./Int_Outputs"

Keith Thompson Over a year ago

@user5231043: Really? The question implies that Int_Outputs is a directory, and the application is called Debug.

TheBBC Over a year ago

Ok, never mind I just saw my mistake, I am missing "Int_Outputs" after "Debug" since that is the executable file and Debug is just the folder.

Collectives™ on Stack Overflow

How to run a executable file in c++ in Linux?

1 Answer 1

3 Comments

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

3 Comments

Related