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In list of dictionaries I would like to find key value containg string.

markets = [ {'symbol': 'BTC/AUD', 'baseId': 'bitcoin'}, {'symbol': 'USD/AUD', 'baseId': 'dollar'}, {'symbol': 'EUR/AUD', 'baseId': 'euro'}, {'symbol': 'ETH/BTC', 'baseId': 'eth'}, ] s = 'BTC' 

I would like to find in symbol values dicts containing a string. For example: Searching for s in markets symbols should return folowing list of dicts:

found = [ {'symbol': 'BTC/AUD', 'baseId': 'bitcoin'}, {'symbol': 'ETH/BTC', 'baseId': 'eth'}, ] 

Any help you can give would be greatly appreciated.

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2 Answers 2

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found = [] for market in markets: if s in market['symbol']: found.append(market) return found 

The above code should return a list of markets containing the value you're looking for. You can also condense this into a one liner:

found = [market for market in markets if s in market['symbol']] 
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1 Comment

I compared timing on your solution and Zeecka. On list with 1800 dictionaries time for your solution was 0.0004906654357910156 and for Zeecka solution - 0.0015139579772949219 so I marked your solution as accepted answer. Thank you both for help.
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You can do either:

found = [] for m in markets: for l in m.values(): if s in l: found.append(m) 

or

found = [m for m in markets for l in m.values() if s in l] 

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