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What would happen if I pull down the INH pin of this IC to GND?

I am unable to understand what would happen if I pulled to GND or make it HIGH?

Can someone help me ?

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What would happen if I pull down the INH pin of this IC to GND?

It's an output (not an input) so I wouldn't go pulling it low in case the internal PMOS is trying to connect it to +Vsupply. From the data sheet page 8: -

The inhibit pin provides an internal switch toward the VS pin which is protected by temperature monitoring. If the device is in normal or Fail-Safe mode, the inhibit high-side switch is turned on. When the device is in Sleep mode, the inhibit switch is turned off, thus disabling the voltage regulator or other connected external devices.

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  • \$\begingroup\$ So, could you tell me what should I connect it to if I am not using? Unable to get clarity? \$\endgroup\$ Commented Oct 20, 2022 at 12:51
  • \$\begingroup\$ You don't need to connect it to anything if you don't use it @Newbie \$\endgroup\$ Commented Oct 20, 2022 at 12:52
  • \$\begingroup\$ Ok, shall I leave it open if I am not using? \$\endgroup\$ Commented Oct 20, 2022 at 12:53
  • \$\begingroup\$ Look on page 8 further down. It is used to enable an external microcontroller. If you don't need that functionality just leave it open (well, I'd connect it to a test point on a PCB just in case and, I might be tempted to connect it to a 10 kohm pull-down resistor too just in case you might want to see what is on the pin). \$\endgroup\$ Commented Oct 20, 2022 at 12:55
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    \$\begingroup\$ The pull-down resistor would not pull it low. In the answer I said don't pull it low and that means don't short it to ground. A pull-down resistor won't short it to ground. \$\endgroup\$ Commented Oct 20, 2022 at 13:16