I did this problem for 7th times now. I did find this question in the book (Alexander Sadiku Fundamental of Electronics), but it's a Pspice problem to find V1 and V2 in each node. This one is source transformation...
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3 - \$\begingroup\$ In the book they used PSpice, so V2 which between branch 2j+2 ohms and 1+2j ohms is V2... the value they got from the simulation is 6.911<-80.72 in the book. \$\endgroup\$Struggling Student– Struggling Student2025-05-04 12:29:46 +00:00Commented May 4 at 12:29
- \$\begingroup\$ I did reverse solution to find I by using ohms law, I = (V2 -18<-30)/(2+2j) and get I = -7.5736-0.3366j. But from the first picture of my solution I got I2 = -7.8182-0.4598 A almost I guess (I'm conflicted) \$\endgroup\$Struggling Student– Struggling Student2025-05-04 12:32:24 +00:00Commented May 4 at 12:32
- \$\begingroup\$ Notice that in the book, R1 = 1Ω and R2 = R3 = 2Ω. But in your circuit, you have R1 = 2Ω; R2 = 1Ω, and R3 = 2Ω. And in this case, V2 = 7.60259 < -83.4105° and I = 7.82861 < -176.625° = -7.8285 - 0.1370j \$\endgroup\$G36– G362025-05-04 13:12:34 +00:00Commented May 4 at 13:12
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