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My question is related to the fundamental problem of portfolio selection, but I am posting it here since in essence the question is really of mathematical optimization. If, however, I am not correct I will move it, for example to quantitative finance.

Consider the following scenario: you have random variables $r_1, \ldots, r_n$, representing rates of return of some financial assets. Let their means be $$ E_s = (E(r_1) , \ldots, E(r_n) )^t $$ and the covariance matrix between the variables be $C$. A portfolio is any linear combination $\omega_1 r_1 + \ldots \omega_n r_n = \omega^tr$ of the assets. Now consider the main optimization problem for construction a portfolio (denoted by $(r)$ ) with a rate of return $r \in \mathbb{R}$ and a minimal variance, i.e., $$ (r)\qquad \begin{aligned} & \underset{\omega\, \in\, \mathbb{R}^n}{\text{minimize}} & & \omega^tC\omega \\ & \text{subject to} & & \omega^t 1_n = 1, \\ & & & \omega^t E_S = r. \; \end{aligned} $$ where $1_n = (1, \ldots, 1)^t$ is a $n$-tuple of ones. Note that there are no restrictions for positivity of the weights (the financial interpretation of the possible negative signs is "short selling"). The problem stated is actually about parametric optimization. In the course Portfolio Selection and Risk Management in coursera (I am linking to the particular lecture) the lecturer explains that to find the solutions for all $r \in \mathbb{R}$ it is sufficient to solve only two problems:

$$ (1) \qquad \begin{array}{cc} \begin{aligned} & \underset{\omega\, \in\, \mathbb{R}^n}{\text{minimize}} & & \omega^tC\omega \\ & \text{subject to} & & \omega^t 1_n = 1.\; \end{aligned} & \qquad \qquad (2) \qquad \begin{aligned} & \underset{\omega\, \in\, \mathbb{R}^n}{\text{maximize}} & & \dfrac{\omega^t E_s - r_f}{\sqrt{\omega^t C\omega}} \\ & \text{subject to} & & \omega^t 1_n = 1. \; \end{aligned} \end{array} $$ and then if their optimal solutions are $\omega_1^*$ and $\omega_2^*$ then all of the solutions of $(r)$ can be produced by linear combinations $$ (*)\qquad \omega_{\lambda} = \lambda\omega_1^* + (1-\lambda)\omega_2^*, \quad \lambda \in \mathbb{R}. $$ /* Here $r_f$ is some positive constant, representing the risk free rate of return */

Graphically, in the standard deviation - expected return space we have the following picture: enter image description here

Indeed, problem $(1)$ is obtained by a relaxation of the constraint $\omega^t E_s = r$ in $(r)$. About problem (2), the target function is the so-called Sharpe ratio, the minimizing of which geometrically is all about minimizing the angle between the red line and the $O\sigma$ axis. The two solutions are depicted with a black and red points.

Finally, here are my questions:

  1. Why can the set of optimal solutions of the parametric problem $(r)$ be obtained by linear combinations of the optimal solutions of $(1)$ and $(2)$?

*It is clear to me that the constraints are preserved under $(*)$ but why $\omega_\lambda$ is optimal for the problem $(\lambda E(r_1^*) + (1-\lambda)E(r_2^*))$, i.e.,

$$ \begin{aligned} & \underset{\omega\, \in\, \mathbb{R}^n}{\text{minimize}} & & \omega^tC\omega \\ & \text{subject to} & & \omega^t 1_n = 1, \\ & & & \omega^t E_S = \lambda E(r_1^*) + (1-\lambda)E(r_2^*)? \; \end{aligned} $$

  1. How is really problem $(2)$ a special case of the problem $(r)$?

Here I would like some rigour.


Credit for the graph: https://people.ucsc.edu/~ealdrich/Teaching/Econ133/LectureNotes/multiAssetOpt.html.

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To solve the portfolio selection problem $(r)$, first we setup the Lagrangian as $$L^{(r)} = \frac12w^tCw$ -\rho_1(w^t1_n-1) - \rho_2(w^tE_S-r).$$ The first order condition yields $$0 = \frac{\partial L^{(r)}}{\partial w} = Cw-\rho_11_n-\rho_2E_S.$$ Thus we have $$w = \rho_1C^{-1}1_n + \rho_2C^{-1}E_S.$$ In other words, $w$ is a linear combination of $C^{-1}1_n$ and $C^{-1}E_S$.

Similarly, we can setup Lagrangian and solve problem $(1)$, which yields a solution of $$w_1^* = \frac{C^{-1}1_n}{1_n^tC^{-1}1_n} \propto C^{-1}1_n$$.

To solve problem $(2)$, we again setup a Lagrangian as $$L^{(2)} = \frac{w^tE_S-r_f}{\sqrt{w^tCw}} - \rho(w^t1_n-1).$$ The first order condition is $$0 = \frac{\partial L^{(2)}}{\partial w} = \frac{E_S}{\sqrt{w^tCw}} - \frac{(w^tE_S-r_f)Cw}{(w^tCw)^{3/2}}-\rho1_n.$$ Rearrange the terms and we have $$w_2^* = \frac{(w_2^{*t}Cw_2^*)}{w_2^{*t}E_S-r_f}C^{-1}E_S-\frac{\rho(w_2^{*t}Cw_2^*)^{3/2}}{w_2^{*t}E_S-r_f}C^{-1}1_n = a C^{-1}1_n + b C^{-1}E_S.$$ As long as $E_S$ is not parallel to $1_n$, you can always decompose the solution of $(r)$ as a linear combination of solution of $(1)$ and $(2)$ as $$w = \alpha w_1^* + \beta w_2^*$$. Since $1 = w^t1_n = w_1^{*t}1_n = w_2^{*t}1_n$, that leads to $\alpha + \beta = 1$, or $$w = \lambda w_1^* + (1-\lambda)w_2^*.$$ So that answers your question 1.

For your question 2., we can see that problem (r) is exactly the problem (2) with one additional constraint $w^tE_S = r$. I guess this is what they meant by 'special case'.

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  • $\begingroup$ Thank you. I also thought about the Lagrange multipliers but somehow didn't believe that the solution $\omega_2^*$ would be expresses so easily as a linear combination of these terms. About my Question 2, I could now say that is unnecessary. $\endgroup$ Commented May 12, 2017 at 16:44
  • $\begingroup$ The problem (2), maximum Sharpe ratio problem, is a nonlinear problem. To solve exactly is a bit messy. As you can see I didn't fully solve for it. I put all the messy stuff into two scalar $a$ and $b$. You can replace problem (2) by a simpler one: (2'): maximize $w^tE_S$, with constraints $w^t1_n = 1$ and $w^tCw = \sigma^2$, and get a similar conclusion. $\endgroup$ Commented May 12, 2017 at 17:02

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