I did the following exercise but even though I've revised my calculations several times, I don't seem to come up with the right answer:
Given a 8-bit processor and the variables $a=30$ and $b=70$, calculate $b-a$ in 2's complement. Indicate if there is a carry-out and overflow.
a. -40, there's overflow and carry-out
b. 40, there isn't overflow but there is carry-out
c. 40, there isn't overflow or carry-out
d. 296, there is overflow and carry-out
Apparently the right answer is b but I don't arrive to the same answer. This is what I do:
I first convert the previous numbers to the binary system.
$$70_{_{10}}=1000110_{2}$$ $$30_{_{10}}=11110_{2}$$
Since, we're dealing with 2's complements, I need to add a 0 at the beggining of each binary number. There:
$$70_{_{10}}=01000110_{2}$$ $$30_{_{10}}=011110_{2}$$
Since, the exercise wants me to subtract, I need to convert 30 to -30. To do that, I flip all the digits of 30 and add 1 up:
$$30_{10}=011110_{2}\Rightarrow 100001_{2} $$ $$100001_{2} + 1_{2} = 100010_{2}$$ Then, $$-30_{10} = 100010_{2}$$ Therefore, I just need to sum them: 
(Since there are more bits in 70 than in -30, I have to add 1s at the beggining of the binary number that represents -30)
Hence, I've found overflow and carry-out and it gives me $100101000_{2}$, which is -216.
Does anyone see the problem?
Thank you in advance.