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Questions tagged [monotone-functions]

In mathematics, a monotonic function (or monotone function) is a function between ordered sets that preserves or reverses the given order. This concept first arose in calculus, and was later generalized to the more abstract setting of order theory. This tag may also include questions about applications or consequences of monotonicity, such as convergence, optimization, or inequalities.

1 vote
2 answers
146 views

Problem statement: Let $f:\mathbb{R} \to \mathbb{R}$ be defined by $$ f(x) = a_1^x + a_2^x + \dots + a_n^x, $$ where $n \in \mathbb{N}, \quad n \ge 3,$ and $a_1, a_2, \dots, a_n > 0,$ all of them ...
Pam Munoz Ryan's user avatar
0 votes
1 answer
83 views

Let $a,b\in \mathbb{R}$ with $a,b>0$. Define the function $f\colon [1,\infty)\rightarrow \mathbb{R}$ by $$ f(x)=(a^\frac{1}{x}+b^\frac{1}{x})^x $$ This function seems to be strictly growing, but I'...
redib's user avatar
  • 49
0 votes
2 answers
180 views

The question: “If a function is not monotone on $(a, b)$, then its square cannot be monotone on $(a, b)$.” We are to provide a counterexample to this statement. On initial attempts I was able to forge ...
relac.ab's user avatar
1 vote
0 answers
89 views

Let $f:\mathbb{R} \to \mathbb{R}$ be a differentiable and one-one function such that $$\lim_{x \to \infty} f(x)$$ exists and is finite. What can we say about $$\lim_{x \to \infty} f'(x)?$$ My ...
Barun Roy's user avatar
0 votes
1 answer
71 views

I've been working for a while on something related to absolutely monotonic functions, and I've come to this realization and it feels like a significant mistake in the literature that I cannot believe ...
Juan Casanova Jaquete's user avatar
0 votes
2 answers
96 views

Edited I've recently been trying to show that in $\mathbb{R}$. If the sequence $(x_n)$ is monotonic for sufficiently large $n$ and it is also bounded, then $(x_n)$ is convergent. I'll present my ...
MathD's user avatar
  • 125
1 vote
0 answers
51 views

Let $ABCD$ be the unit square. $A(0,0,0),\; B(1,0,0),\; C(1,1,0),\; D(0,1,0)$ For $k\in[0,1]$, define $$ P(k)=(k,0,0),\qquad Q_0(k)=(k,1,0). $$ Now rotate the top edge $CD$ by an angle $\theta$ around ...
user1693987's user avatar
3 votes
2 answers
151 views

Let $f$ be a decreasing derivable function on $(0,+\infty)$, and $g$ be a positive derivable function on $\mathbb{R}$. If $g'(x)=f(g(x))$, and $g'(x)$ has a zero, is $g$ a constant function? I set $...
JC Q's user avatar
  • 2,104
4 votes
1 answer
153 views

Let $f:\mathbb R\to\mathbb R$ real analytic function on $\mathbb R$. Suppose that its Taylor series around $x=0$ is $$ S(x) = \sum_{k=0}^\infty (-1)^k\,a_k\,x^k$$ where $a_k\geq0$ for all $k$. In ...
tituf's user avatar
  • 993
3 votes
1 answer
177 views

In the paper Ciesielski and Miller. A continuous tale on continuous and separately continuous functions. Real Analysis Exchange Vol. 41(1), 2016, pp. 1-36. the following theorem appears: Theorem 11. (...
Enrico's user avatar
  • 389
2 votes
0 answers
141 views

Let $f:\mathbb R \to \mathbb R$ real analytic function. Suppose that $f^{(k)}(0)\geq0$ for all $k=0,1,2,\dots$ (where $f^{(0)}$ denotes the functions itself and $f^{(k)}$ the $k^{th} $ order ...
tituf's user avatar
  • 993
0 votes
1 answer
104 views

I met an interesting function defined by series of functions, which is given as follows \begin{equation*} f(n,s)=\frac{s}{n(n+1)}-\sum_{k=0}^{+\infty}\frac{2s}{(sk+n)(sk+n+1)(sk+n+2)}. \end{equation*} ...
W.J's user avatar
  • 405
1 vote
2 answers
87 views

Recently, I met an interesting function when studying higher-order moments of a class of distributions, which is given as \begin{equation*} g(n,s) = \psi\left(\frac{n+2}{s}\right)+\psi\left(\...
W.J's user avatar
  • 405
9 votes
2 answers
357 views

$\DeclareMathOperator{\th}{th}$ A Boolean function $f:\{0,1\}^n \to \{0,1\}$ is monotone if for all $a_1,\dots,a_n,a'_1,\dots,a'_n$, if $a_i \leq a'_i$ for all $1 \leq i \leq n$ then $f(a_1,\dots,a_n) ...
mathperson314's user avatar
1 vote
0 answers
61 views

I am working with ordinal arithmetic at the moment, more precisely with ordinals below epsilon zero. Further I am considering the Hardy computation as a ordinal indexed hierarchy of functions as ...
CopperCableIsolator's user avatar

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