Javascript - How to check if a string contains multiple substrings

Question

I have multiple sub-strings that I want to find in a single string and if all three are found then do this, if not, do something else.

I am kind of stuck on how to set it so that if I get three "True", I want to execute something, other I want it to do something else.

Many thanks.

My code is below.

//Main String var string0 = ' ": {"MATHEMATICS": {"status": "start", "can_start": false}, "READING": {"status": "start", "can_start": false}, "WRITING": {"status": "start", "can_start": false" '; //Substrings var substringArray = ['"MATHEMATICS": {"status": "start"', '"READING": {"status": "start"', '"WRITING": {"status": "start"']; //Check if Substrings are found in MainString for (l = 0; l < substringArray.length; l++) { if (string0.indexOf(substringArray[l]) > -1) { logger.info("True"); } else { logger.info("False"); } }

Telman · Accepted Answer · 2016-06-09 00:56:57Z

You can try use Array.every method to check for all the substrings.

An example of code:

var isContainsAllTheParts = substringArray.every(function(substring){ return string0.indexOf(substring) >= 0; });

SenthilKumarM · Accepted Answer · 2016-06-09 00:51:08Z

Simply use a variable to count the number of "true"

 //Main String var string0 = ' ": {"MATHEMATICS": {"status": "start", "can_start": false}, "READING": {"status": "start", "can_start": false}, "WRITING": {"status": "start", "can_start": false" '; //Substrings var substringArray = ['"MATHEMATICS": {"status": "start"', '"READING": {"status": "start"', '"WRITING": {"status": "start"']; var matchCount = 0; //Check if Substrings are found in MainString for (l = 0; l < substringArray.length; l++) { if (string0.indexOf(substringArray[l]) > -1) { logger.info("True"); matchCount++; } else { logger.info("False"); } } if(matchCount == 3){ //do something logger.info('I did'); } else { // do some other thing logger.info('I did not'); }

Thanks, we posted at the same time! I have marked yours as the answer. Thank you :)
use substringArray.length instead of hard coded 3, then it will work for any number of elements in substringArray

VitUrsa · Accepted Answer · 2020-11-12 20:45:41Z

Not sure why Telman Ahababov's answer wasn't accepted. I'll explain it in case it wasn't clear enough. I'm also shortening it up a bit more and using the simpler includes() method:

let str = "Here is the string in which we want to find multiple substrings." let subStrArr = ["Here is", "which we", "multiple"] let containsAllSubStrs = subStrArr.every(subStr => { return str.includes(subStr); }); if (containsAllSubStrs) { //containsAllSubStrs equals 'true', meaning all substrings were found. } else { //containsAllSubStrs equals 'false', meaning NOT all substrings were found. }

lamdan · Accepted Answer · 2016-06-09 00:51:15Z

I figured out a way to do it.

var magicNumber = 0; //Check if Substrings are found in string0 for (l = 0; l < substringArray.length; l++) { //logger.info(substringArray[l]); if (string0.indexOf(substringArray[l]) > -1) { logger.info("True"); magicNumber++; } else { logger.info("False"); } } while (magicNumber < 3) { //execute this }

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