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I just stumbled over a script with works in bash but not in zsh:

if [ Darwin = `uname` ]; then library_path=DYLD_LIBRARY_PATH else library_path=LD_LIBRARY_PATH fi if [ -z "${!library_path}" ]; then eval ${library_path}=${thisdir}/lib64:${thisdir}/lib; export ${library_path} else eval ${library_path}=${thisdir}/lib64:${thisdir}/lib:${!library_path}; export ${library_path} fi

the second if should apparently test, depending on the kernel, if $LD_LIBRARY_PATH is non zero, or if $DYLD_LIBRARY_PATH is non zero. And then either set or expand the respective variable.

How would I do the same in zsh? And is there a version that works in zsh and bash?

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It appears $(eval echo \$\{$library_path\}) works:

if [ Darwin = `uname` ]; then library_path=DYLD_LIBRARY_PATH else library_path=LD_LIBRARY_PATH fi if [ -z $(eval echo \$\{$library_path\}) ]; then eval ${library_path}=${thisdir}/lib64:${thisdir}/lib; export ${library_path} else eval ${library_path}=${thisdir}/lib64:${thisdir}/lib:$(eval echo \$\{$library_path\}); export ${library_path} fi

though there might be a more elegant solution.

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  • That's wrong (and potentially dangerous) as you're also evaluating the content of $thisdir as shell code as well . You also don't need to use echo or process substitution (especially unquoted!) here. Commented Oct 25, 2016 at 22:20
  • See the dup Q&A for the zsh equivalent of bash's ${!var} or the proper way to use eval Commented Oct 25, 2016 at 22:23

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