Ubuntu 16.04
I tried this:
for file in $source/*.zip do echo $file done and it works if the directory contains zip files. It prints out all them. But if it does not, it just print the $source/*.zip. I mean if source=/home/usrname/dir which does not contain any zips then it prints
/home/usrname/dir/*.zip Is there a way to make it print nothing in that case?
You could use:
find "$source" -name "*.zip" And if needed pipe it to xargs or use:
shopt -s dotglob for file in "${source}"/*.zip do if [ -f "${file}" ]; then printf '%s\n' "$file" fi done To print only the zip files that are regular files or symlinks to regular files.
bashshopt -s nullglob dotglob files=("$dir"/*.zip) ((${#files[@])) && printf '%s\n' "${files[@]}" shopt -u nullglob dotglob # if needed zshfiles=($dir/*.zip(ND)) (($#files)) && printf '%s\n' $files fishset files $dir/.*.zip $dir/*.zip if count $files > /dev/null printf '%s\n' $files end (beware it would omit a file called .zip though (contrary to the other solutions given here)).
ksh93FIGNORE='@(.|..)' files=(~(N)"$dir"/*.zip) ((${#files[@])) && printf '%s\n' "${files[@]}" unset FIGNORE # if needed yashset -o dot-glob -o null-glop files=("$dir"/*.zip) [ "${files[#]}" -gt 0 ] && printf '%s\n' "$files" set +o got-glob +o null-glob # if needed export LC_ALL=C set -- "$dir"/[*].zip "$dir"/*.zip case ${1##*/}${2##*/} in '[*].zip*.zip') shift 2 esac set -- "$dir"/.[*].zip "$dir"/.*.zip "$@" case ${1##*/}${2##*/} in '.[*].zip.*.zip') shift 2 esac [ "$#" -gt 0 ] && printf '%s\n' "$@" 