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I'm learning C and in general I code with VS Code in Ubuntu. For convenience, I'm trying to migrate my learning materials to Windows where a lot of my other works happen, so I installed WSL 2 and its distro Ubuntu 18.04 LTS. After installing VS Code for Windows and its remote extension to work with WSL, I boot up a new WSL session in VS Code, install the C/C++ extension with IntelliSense then write a simple program like below just for demonstration:

#include <signal.h> int main() { kill(-1, SIGKILL); }

The problem with VS Code is that while the program compiles, its IntelliSense doesn't detect the kill function in the signal.h header. By further investigating the header file, I observe that the following part is darkened

#ifdef __USE_POSIX extern int kill (__pid_t __pid, int __sig) __THROW; #endif /* Use POSIX. */

along with other parts where __USE_POSIX is checked, including but not limited to siginfo_t, struct sigaction.

Is there a way to make VS Code recognise these macros/variables to enable IntelliSense's assistance?

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2 Answers 2

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You could either add #define __USE_POSIX above where you include the header in question, or if you want to define it as a compiler arg (Perhaps through a -D flag or via CMake or something), the file .vscode/c_cpp_properties.json allows you to specify which flags are being used this way like so:

"configurations": [{ "defines":["__USE_POSIX"] }]

See https://github.com/Microsoft/vscode-cpptools/issues/304 for further information on this feature.

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the following config is effective

"configurations": [{ "defines": ["_XOPEN_SOURCE"] }]
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  • Please explain how to use this.  Also, can you explain how/why it works? Commented Aug 19, 2024 at 18:58

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