I have a file with numbers in like this:
1234 5678 3456 How can I get this on one line using a bash shell script with a space between each like this
1234 5678 3456 
- Do you know it's going to be three lines in your file, or may there be a thousand or more lines?Kusalananda– Kusalananda ♦2021-07-15 15:44:38 +00:00Commented Jul 15, 2021 at 15:44
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2 Answers
The easiest way is to use xargs. e.g.
xargs < file.txt 
- 1well, it'll only work if all the numbers will fit into one shell command line. I don't know what the line length limit is on hp-ux, but on linux it's about 2 million characters. If there's more than will fit in one line, xargs will print a second (or third...) line.cas– cas2021-07-15 15:54:56 +00:00Commented Jul 15, 2021 at 15:54
- Daft question - the max there will be is 8 sets of numbers. I then want to read the file.txt and make that into a variable called numbers so that when numbers is called it contains 1234 5678 3456. I know there will be some quoting cus of spaces but unsure how to do it.Steve– Steve2021-07-16 07:05:57 +00:00Commented Jul 16, 2021 at 7:05
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- I'm also trying work out a way that when I read a users input for the numbers that I don't output letters, a number below 1000 or over 9999 to the file im using. I have this but I don't think its right.Steve– Steve2021-07-16 14:02:41 +00:00Commented Jul 16, 2021 at 14:02
- # Loop to check the numbers entered by user are valid and outputs them # to a file called numbers.txt # The loop will only let you enter numbers from 1000 to 9999 x=0 until [ ! $x -ne $br2update ] do echo "Enter number" read store if [ $store -gt 1000 ] && [ $store -lt 9999 ] then echo $store >> numbers.txt x=
echo "$x + 1" | bcelse echo "Invalid number" fiSteve– Steve2021-07-16 14:44:44 +00:00Commented Jul 16, 2021 at 14:44
paste -sd' ' file 