Hi I have the following program. When I compile on the terminal gcc main.c I do get an executable named a.out. However if I type a.out in the terminal I get the following message: a.out: command not found
Any ideas on what I might be doing wrong?
#include <stdio.h> #include <stdlib.h> #define PROMPT "print something" /* * */ int main() { printf("CS-xxx Assignment x, xxxxx\n"); printf(PROMPT); return (EXIT_SUCCESS); } Assuming you use a Unix-based system, usually "." is not in the path: So, try ./a.out
Try using
./a.out Most Linux systems will not look in the current directory for executables, so you need to tell it to look in the current directory.
You might not have "." (current directory) in your PATH environment variable.
Try running "./a.out" or add "." to your PATH.
Use
./a.out
You must run program specifying current directory.
Just type ./a.out and things should work. The issue is without ./ the shell thinks you are typing in a command.
$PATH.Must run all the c, c++, shell programs by specifying directory path under unix family. the symbol ./ should specify the current directory.
Examples: ./kernel (kernel elf is in current directory) ../kernel (kernel elf is in parent directory of current directory) childdir/kernel (kernel elf is in child directory of current directory)
Use ./a.out now you are able to execute your executable file. This ./ is basically denotes find in current directory.
I think now you get what you have to do.
