How to get $\langle x|p \rangle$, just by using $[\hat{x},\hat{p}]=i\hbar$, and $\langle x^{\prime}|x^{\prime\prime} \rangle=\delta(x^{\prime}-x^{\prime\prime}),\langle p^{\prime}|p^{\prime\prime} \rangle=\delta(p^{\prime}-p^{\prime\prime})$ ? There are many proofs for this simple question, however, is there some way more elegant to deduce?
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