Echoing PHP within HTML

Question

I am currently trying to create a shopping cart for my website and I have images of products stored in a database and I want to include them within <img src> . By putting $get_row[imagesrc] within the src. I need to know the correct way to add it to the below code as I dont fully understand the ' and . tags

 echo '<p>'.$get_row['name'].'<br/>'.$get_row['description'].'<br/>'.$get_row['imagesrc']. '<br/>&pound;'.number_format($get_row['price'],2).'<a href="cart.php?add='.$get_row['id'].'">Add</a></p>';

You will really get mad in generating html this way - get into some templating engine like Smarty or Twig. — moonwave99
– moonwave99, Commented Jan 7, 2013 at 17:15

BenM · Accepted Answer · 2013-01-07 17:15:10Z

This should achieve what you're looking for:

echo '<p>'.$get_row['name'].'<br/>'.$get_row['description'].'<br/><img src="'.$get_row['imagesrc'].'" /><br/>&pound;'.number_format($get_row['price'],2).'<a href="cart.php?add='.$get_row['id'].'">Add</a></p>';

The ' character defines a string literal when it is wrapped around a series of characters.
The . character is used for concatenating strings for output or storage.

abhshkdz · Accepted Answer · 2013-01-07 17:15:43Z

echo '<p>'.$get_row['name'].'<br/>'.$get_row['description'].'<br/><img src="'.$get_row['imagesrc'].'"><br/>&pound;'.number_format($get_row['price'],2).'<a href="cart.php?add='.$get_row['id'].'">Add</a></p>';

Toddish · Accepted Answer · 2013-01-07 17:19:02Z

. concatenates two strings, and ' is wrapped around a string.

so

echo 'Hello '.'World'; // Shows Hello World

I'd split yours up to make it easier to read:

echo '<p>'; echo $get_row['name'].'<br/>'; echo $get_row['description'].'<br/>'; echo '<img src="'.$get_row['imagesrc'].'" /><br/>'; echo '&pound;'.number_format($get_row['price'],2); echo '<a href="cart.php?add='.$get_row['id'].'">Add</a>'; echo '</p>';

But it all looks OK.

Pedro del Sol · Accepted Answer · 2013-01-07 17:14:42Z

echo '<p>'.$get_row['name'].'<br/> <img src="'.$get_row['imagesrc'].'" alt="'.$get_row['name'].'"><br/> <br/>&pound;'.number_format($get_row['price'],2).' <a href="cart.php?add='.$get_row['id'].'">Add</a></p>';`

BenM · Accepted Answer · 2013-01-07 17:15:34Z

1

echo '<img src="'.$get_row['imagesrc'].'">';

Try that.

edited Jan 7, 2013 at 17:15

BenM

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answered Jan 7, 2013 at 17:15

SeanWM

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Comments

Community · Accepted Answer · 2017-05-23 12:14:23Z

A specific answer has been given:

echo '<img src="'.$get_row['imagesrc'].'">';

Nonetheless, it's worth adding that you should:

You should escape output - with htmlspecialchars() or otherwise.

echo '<img src="' . htmlspecialchars($get_row['imagesrc']) . '">';

Read the documentation on PHP Strings.

phpisuber01 · Accepted Answer · 2013-01-07 17:18:43Z

Check out this way of including PHP in your HTML. It's much easier to read and maintain. The last line in the paragraph is your image tag.

<p> <?php echo $get_row['name']; ?><br/> <?php echo $get_row['description']; ?><br/> <?php echo $get_row['imagesrc']; ?><br/> &pound;<?php echo number_format($get_row['price'],2); ?> <a href="cart.php?add=<?php echo $get_row['id']; ?>">Add</a> <img src="<?php echo $get_row['imagesrc']; ?>" /> </p>

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